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# The number of photons per unit cubic meter at 1000 k are MCQ

And it's this n over t that we are interested in— the number of photons per time— and that'll be photons per second if we choose our units for everything else correctly. And energy per photon we'll replace with Planck's constant times frequency from here. And so multiply both sides by 1 over hf and multiply this by 1 over hf. And so we have. Some pulse LIDAR systems operate in single photon counting mode using TCSPC to achieve higher resolution. Measured quantities. The number of photons observed per unit time is the photon flux.The photon flux per unit area is the photon irradiance if the photons are incident on a surface, or photon exitance if the emission of photons from a broad-area source is being considered Photons are bosons so unlike fermions such as electrons there is no restriction on multiple photons occupying the same energy state. Consequently there is no limit on the number of photons you can put in your box. There is an upper limit to the total energy density in the box since if you make it too high the box willcollapse into a black hole Then Number of photons = Total energy/Energy of one photon Few instructors will make the question so simple. Instead, they might disguise it as follows. EXAMPLE A common laser pointer produces 1.0 mW at a wavelength of 670 nm. Calculate the number of photons produced per millisecond. Solution Step 1. Calculate the energy of a photon If you say How many photons per cubic meter can coexist in a cubic kilometer, or a cubic lightyear? then you will get a nice big number because you can include very weak photons with very long wavelengths! But if you insist on imagining a 1 cubic meter box and say How many can coexist in this box

### OpenStax College Physics Solution, Chapter 29, Problem 31

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2. Now to find the NUMBER OF PHOTONS (per unit volume) all we do is divide the energy density by the average energy per photon at temp T, which IIRC is equal to 2.701 kT. As i recall this is a fact about thermal radiation. If this is right then the number of photons per cubic meter that is in the room with you is given b
3. 18.13 a) an ideal boson gas consists of 4He atoms whose Bose temperature is 0.087 K. Find the boson concentration, the number of bosons per cubic meter. Use equation 18.37 () 3 26 27 26 3 2
4. g that all the photons have the wavelength of 1.1 mm at which the energy density is a maximum
5. ed from Hall measurements (Section 28-4). Units inverse cubic meter (m-3) Electrical Properties of Solids 41-Fig. 41-1 copper silicon or carbon Face-centered cubic Diamond lattic

### Photon counting - Wikipedi

1. ed as shown in Eq. 8. Multiply the number of photons per meter2 by the area of a pixel in meters and the result is the number of photons a pixel collects in an 18 percent gray area. ppm2=H*kpls (8
2. Photons are not matter. They cannot produce a Gravitational Field, no matter how many of them you can in a volume. That said, photons will convert into electrons and positrons, which will then annihilate each other into photons again. As far as I.
3. (a). The average energy per photon is given by the ratio of the total energy density u= aT4 and the total number density of photons, which from Q9.2(b) is n= 16ˇ (3) kT hc 3: Thus, u n = ah 3c 16ˇ (3)k4 kT= 2:70kT; which is the desired result (b). For the center of the Sun T= 1:57 107 K, giving u=n= 5:85 10 16 J = 3:65keV; whereas fo

(a) Show that the total number of photons per unit volume at Temperature T is N/V = 8 Pi (kT/hc)^3 Integrate limit between 0 to infinity x^2 dx/ (e^x-1). (b) 11w value of the intcral is about 2.404. How many photons per cubic centimeter are there in a cavity filled with radiation at T= 300 K? At 3 K Answer: (d) When photons are incident on the diode, the fractional change in the reverse current is much greater than the fractional change in the forward current. Q3: The maximum wavelength of photons that can be detected by a photodiode made by a semiconductor of bandgap 2eV is about. 620 nm; 700 nm; 740 nm; 1240 nm; Answer: (a) 620 n The energy of a single photon is a tiny number given by the Planck's equation. The Planck's equation relates the frequency of a photon to its energy through a Planck constant h equal to. h = 6.6261 × 10 −34 J*s. The Planck constant is in the units (energy)*(time) and you can think of it as a conversion factor from energies to frequencies

The becquerel (English: / b ɛ k ə ˈ r ɛ l /; symbol: Bq) is the SI derived unit of radioactivity.One becquerel is defined as the activity of a quantity of radioactive material in which one nucleus decays per second.For applications relating to human health this is a small quantity, and SI multiples of the unit are commonly used. The becquerel is named after Henri Becquerel, who shared a. number of photons per unit volume N γ but not an absolute number of photons. Defining n (E) to be the number of photons per unit energy per unit volume, then the number of photons (per unit volume) having energy between E and E + dE is n(E) dE. For a gas of photons in equilibrium, this number density is given by n(E)dE= 8! (hc)3 E2dE eE/kT-1 n. The number of photons depends on their energy and the power of the source. For each Watt, at a wavelength of 550 nm (middle of the visible spectrum) the number of photons you have is about 2.77 x 10^19 per second. If the light is of a longer wavelength you have more photons Finally, to find the number of photons per second falling on these pages, we have to divide P book by the energy per photon. Number of visible photons from bulb hitting the book per second = (0.017 J/s)/(3.61* 10-19 J) = 4.7*10 16 /s. This is not an accurate number, but a useful, order of magnitude estimate

The average matter density in the universe is roughly 1 nucleon per cubic meter. So photons outnumber matter particles at a rate of 10 8 or 10 9 to 1 The rate of heat transfer to the classroom through the walls and the windows is estimated to be 15,000 kJ/hr. If the room is to be maintained at a constant temperature of 21°C, determine the number of window air-conditioning units required. A. 1 units. B. 2 units. C. 3 units. D. 4 units

Calculate the wavelength at which the CMB is a maximum and, to make the units consistent, convert this wavelength from nanometers to meters. Reference: Exercise 29.27 Continuing the thinking in Exercise 29.27 and Exercise 29.28 , calculate the energy in a cubic meter of space, multiply the energy per photon calculated in Exercise 29.26 by the. Gamma rays, a form of nuclear and cosmic EM radiation, can have the highest frequencies and, hence, the highest photon energies in the EM spectrum.For example, a γ-ray photon with f = 10 21 Hz has an energy E = hf = 6.63 × 10 −13 J = 4.14 MeV. This is sufficient energy to ionize thousands of atoms and molecules, since only 10 to 1000 eV are needed per ionization That one second corresponds to a volume of 3e8 cubic meters, so after division, you get about 10 trillion (1e13) photons per cubic meter. 3.6K view Since the energy of a photon of wavelength λ is h*c/λ (unit is in joule, if λ is in meters), it's straightforward to calculate the radiant flux (the number of photons produced per second) of. Cleanrooms are classified according to the number and size of particles permitted per volume of air. Large numbers like class 100 or class 1000 refer to FED_STD-209E, and denote the number of particles of size 0.5 µm or larger permitted per cubic foot of air

### How many photons can exist in a cubic box of unit volume

Note that the units of the radius were cubed along with the value, so our volume has units of cubic kilometers. Now we can calculate the density: density = mass/volume density = 1.8 x 10 21 kg / 1.07 x 10 9 km 3 density = 1.67 x 10 12 kg/km 3. Now this is a perfectly valid answer with perfectly valid units number of available states in a cubic cm per unit of energy, the density of states, is given by: eV cm Number of States unit E E m m E E g E E E m m E E g E v corresponds to a wave number k f. This value of k f, defines a volume in k-space for which all the electrons must be within. 3. We then simply take the ratio of the total volume. Stromgren Sphere Approximate size of H II region (19) u R s = radius of sphere (m) N uv = number of UV photons emitted/sec N e = number of electons per cubic meter N H = number of H atoms per cubic meter a(2) = recombination coefficient = 10-19 m3/s Chapter 4 Mass of galaxies - Kepler's Third Law Mass(R) = R v2/G (20) Mass(R) = Mass contained within radius R, k A +n indicates the number of zeros that follow the number 10, thus for n = 3, the value of 10 3 is 1 followed by three zeros, or 1000 (this is the same as the cube of 10). The number 10 6 is 1000000, i.e., a 1 followed by six zeros to its right (note: 10 0 = 1). Thus, 10 60 represents 1,000,000,000,000,000 out to 60 such zeros

### How do you calculate the number of photons? + Exampl

This Multiple Choice Questions will help ICSE and CBSE students to prepare well for their Examinations. 40 cm wide, and 20 cm Deep is made up of iron that weighs 50 kg per cubic meter? a) 15 kg b) 39 kg c) 29 kg d) 36 kg. Answer √(l²+b²+h²) Cubic Units b) (lxbxh) Cubic Units c) a 3 Cubic Units d) a√3 Cubic Units. Answer. 37 Full PDFs related to this paper. READ PAPER. solution manual of physics by arthur beise Start studying Chemistry 103 Ch. 1+2. Learn vocabulary, terms, and more with flashcards, games, and other study tools ### Photons in 1 cubic meter Physics Forum

• You can calculate for yourself how many CMB photons are in a cubic meter of the space out between the stars. I just calculated it, using Google calculator, and it came to about 400 million photons per cubic meter. Here is what I typed into the google window 0.24*(k*2.728 kelvin/(hbar*c))^3 then I pressed return and it said 411 million per cubic.
• 2. Calculate the number of donor atoms per m 3 of n-type material having resistivity of 0.25 Ω-m, the mobility of electrons is 0.3 m 2 /V-s. Sol: We know: [Since n = number of free electron per m 3 ≈ number of donor atoms in n-type] 3. At 300 K, find the diffusio
• NTP - Normal Temperature and Pressure - defined as 20 o C (293.15 K, 68 o F) and 1 atm ( 101.325 kN/m2, 101.325 kPa, 14.7 psia, 0 psig, 30 in Hg, 760 torr); Molecular weights can be used to calculate Specific Gravity if the densities of the gas and the air are evaluated at the same pressure and temperature
• g interview of CIL MT,ESE,PSU,DMRC,NMRC etc. We will be upload more PDF in upco
• We chose a photon counting and thin target technique to measure the pressure dependence of photon yields (the number of photons produced by electrons per meter of travel) from nitrogen and air excited by electrons, following the method employed by Kakimoto et al. .The cubic chamber used is shown schematically in Fig. 1.Three photomultiplier tubes of 2 in. diameter (Hamamatsu photon counting.

1 L = 1000 mL, 1000 cm 3 = 1 dm 3; Density: It is the amount of mass per unit volume. Its SI unit is kilogram per cubic meter (kg/m 3) Another common unit is gram per cubic meter (g/cm 3). Temperature: It is the degree of heat present in a substance. Its SI unit is Kelvin (K) Another common units are: Degree Celsius (°C) and degree Fahrenheit. (b) What is the power output of the sun, and how many photons per second does it emit? (c) How many photons per cubic meter are there near the earth? (Beiser, Ex. 9, pg. 90) Solution. 1.5 mW of 400-nm light is directed at a photoelectric cell. If 0.10 percent of the incident photons produce photoelectrons, find the current in the cell

### homework and exercises - Total number of photons per unit

1. Multiple choice questions (10 points) Answer by circling one of (a), (b), (c), etc. directly on the test paper|except for question 2, where you'll need to write the letters into the four blanks, and question 3, where you'll circle either true or false. Be sure that each selection is clear and unambiguous
2. There are 1.36 kg of gas, for which R = 377 J/kg.k and k = 1.25, that undergo a nonflow constant volume process from p1 = 551.6 kPa and t1 = 60°C to p2 = 1655 kPa. During the process the gas is internally stirred and there are also added 105.5 kJ of heat
3. Volume is commonly quantified numerically using the SI derived unit, the cubic meter. Capacity is the ability to hold a fluid, very similar to volume. However, volume and capacity are sometimes distinguished: first, capacity is used for how much a container can hold (with contents measured commonly in liters or its derived units), and volume.
4. The linear attenuation coefficient (µ) describes the fraction of a beam of x-rays or gamma rays that is absorbed or scattered per unit thickness of the absorber. This value basically accounts for the number of atoms in a cubic cm volume of material and the probability of a photon being scattered or absorbed from the nucleus or an electron of.
5. Mean Free Path The mean free path or average distance between collisions for a gas molecule may be estimated from kinetic theory. Serway's approach is a good visualization - if the molecules have diameter d, then the effective cross-section for collision can be modeled by . using a circle of diameter 2d to represent a molecule's effective collision area while treating the target molecules as.
6. The actual density of hydrogen as it exist in interstellar space is on the average of about 1 atom per cubic centimeter. In the extremes, as low as 0.1 atom per cubic centimeter has been found in the space between the spiral arms and as high as 1000 atoms per cubic centimeter are known to exist near the galactic core

Hi K. Blair, The conversions are as follows: 1 microgram (mcg or µg) = 0.001 milligrams (mg) 1 microgram (mcg) = 1000 nanograms (ng) 1 milligram (mg) = 1000 micrograms (mcg) 1 gram (g) = 1000 milligrams (mg) Converting mcg to mg To convert mcg to mg you simply divide your value by 1000 (or multiply by 0.001) Calculate the ratio of the number of allowed energy levels at 8.5 eV to the number of allowed energy levels at $7.0 \mathrm{eV}$. (b) Cop per has a Fermi energy of 7.0 eV at 300 K. Calculate the ratio of the number of occupied levels at an energy of 8.5 eV to the number of occupied levels at the Fermi energy A watt is a unit of energy per unit of time, and one watt (W) is equal to one joule per second. An 80.0-W incandescent lightbulb produces about 5.00% of its energy as visible light. Assuming that t..

### Photons in 1 cubic meter at temp T Physics Forum

1. If Q is discharge is cubic meters per sec and D is the economical diameter of the pipe. According to Lea 750 to 1000 (D) 1000 to 1250. Correct Answer View All Answers Multiple Choice Questions with Answers on Refrigeration and Air-Conditioning - Set 07. Practice Test: Question Set - 07 1..
2. Specific heat of steam ≈ 0.48 calories/g· o C Absolute viscosity of water at 20 o C = 1.0019 centipoise (cp) = 0.0010019 Pascal-seconds (Pa·s). Surface tension of water (in contact with air) at 18 o C = 73.05 dynes/cm. pH of pure water at 25 o C = 7.0 (pH scale = 0 to 14). Properties of Dry Air at sea leve
3. Calculate the change of entropy per kg of air (R = 0.287 KJ/kg-K; k = 1.4) when heated from 300 K to 600 K while the pressure drops from 400 KPa to 300 KPa. ( S = 0.78 KJ/kg-K) 106. A 5 kg quantity of oxygen (M = 32; k = 1.395) is heated from 250 K to 400 K at constant pressure

The linear attenuation coefficient (µ) is the actual fraction of photons interacting per 1-unit thickness of material. In our example the fraction that interacts in the 1-cm thickness is 0.1, or 10%, and the value of the linear attenuation coefficient is 0.1 per cm 55) If the percentage of free respirable silica present is 10% in the atmosphere , what is thepermissible limit of free silica in milligrams per cubic meter of air sampled. a) 1.5 b) 3 c) 10 d)

### statistical_test.pdf - PH102 Statistical Mechanics ..

Make sure to memorize the density of pure water, which is 1000 kg/m3 (or 1 g/cm3, or 1 kg/L; you should know this value in multiple different units). Finally, ensure that your units align by converting volume to cubic meters. 1 cm3 = 1 × 10-6 m3, so 60 cm3 = 60 × 10-6, or 6 × 10-5, m3 A. Attenuation per gram depends on the Z of the absorber. B. The interaction is primarily with inner bound electrons. C. It is the dominant process for photons in the 5-10 keV range interacting with tissue. D. Attenuation per gram depends on the electron density. G62. The energy absorbed in pair production is: A. The incident photon energy, E

### Is there a maximum amount of light that can fit in a cubic

As there are 1,000 micrograms (mcg) in 1 milligram (mg), you can work out your answer by multiplying your mg figure by 1000. How many mg are there in a mcg? 1mcg = 1/1000mg. There are 1,000 micrograms in 1 milligram. To work out your answer, divide your mcg figure by 1000. mcg to mg; mg to mc Calculate the energy per photon and the number of photons emitted per second from 200 W/s Short Wave UV Light with a wavelength of 280 nm. S10.3B Equation for frequenc Similarly, volume is a derived quantity that can be expressed in cubic meters (m 3). Speed is length per time; so in terms of SI base units, we could measure it in meters per second (m/s). Volume mass density (or just density) is mass per volume, which is expressed in terms of SI base units such as kilograms per cubic meter (kg/m 3). Angles can. Let N be the number of atoms per unit volume and n be the number of free electrons per unit volume. Then, the number of free electrons per atom is n / N. We use the result of Problem 41-7 to find n: E F = An 2/3, where A = 3.65 × 10 -19 m 2 · eV. Thus, g, 1000 cu. cm = 1 cu. decimeter 1000 cu. dm = 1 cu. meter 1 million cu. cm = 1 cu. meter: Capacity 10 milliliters = 1 centiliter 10 centiliters = 1 deciliter 10 deciliters = 1 liter 1000 liters = 1 cu. meter : Mass/Weight 1,000,000 microgram = 1 gram 1000 milligram = 1 gram 1000 grams = 1 kilogram 1000 kilograms = 1 ton

Common Weights and MeasuresLength1 millimeter = 1/1,000 meter1 centimeter = 1/100 meter1 decimeter = 1/10 meter1 meter (basic unit of length)1 dekameter = 10 meters1 kilometer = 1,000 meters1 inch = 1/36 yard = 1/12 foot1 foot = 1/3 yard1 yard (basi A2A This is a question that is a bit complex to answer, but in general the idea behind it — that the energy density is low and the explosion vast only because of volume — is not correct. First there are different types of supernovas with very diff.. Figure 2: The curve shown in Figure 1 is normalised so that the area of the curve is 60W. Since the energy of a photon of wavelength λ is hc/λ (unit is in joule, if λ is in meters), it's straightforward to calculate the radiant flux (the number of photons produced per second) of the light bulb.The numbers are plotted in Figure 3 In sodium there are approximately 2.6 x 10 28 conduction electrons per cubic meter, which behave as. Show that for aluminium at T = 1000 K, differs from by less than 0.01 %. Calculate the number of photons in equilibrium in a cavity of volume 1 m 3 held at a temperature T = 273 K. (b) Compare this number with the number of molecules the.

### Solved: (a) Show That The Total Number Of Photons Per Unit

In the context of the photoelectric effect, the key thing to remember is that you get one electron per photon. Current is a measure of how much charge flows per unit time, which is proportional in this case to the number of electrons per unit time, and therefore the number of photons per unit time (ten miles per hour) has a kinetic energy of 12.5 joules per cubic meter. Applying Betz's Applying Betz's Law, which limits efficiency to 59% (Bet z 1926), yields about seven joules per cubic There are 1000 litres in a cubic metre, so the mass of 1 cubic metre of water is approximately 1000 kilograms or 1 metric ton. The mass of a nickel is 5 g A US nickel weighs 5 grams, and a penny weighs 2.5 grams

### MCQs on Photodiode For NEET 202

• The watt is the derived SI unit of power, the measure of energy per unit time: 1 W = 1 J/s. A semiconductor laser in a CD player has an output wavelength of 780 nm and a power level of 0.10 mW. How many photons strike the CD surface during the playing of

### Photon

• E = mc2, what is the equivalent mass density, in kilograms per cubic meter? What fraction of the critical density, ρ crit = 10−26 kg/m3, does this density represent? First, compute the energy density of the CMB. We know the number of photons per unit volume (n CMB = 4.11 × 108 photons / m3) and the average energy that each carries (E = 1.02.
• Mechanics of Solids MCQ question on Simple Stress and Strain. Muthu Vikki. Download PDF. Download Full PDF Package. By Sarath Sankar K S Asst. Prof in ME. Schaum's Outlines Strength of Materials. By hisham hanafy. Design of Machine Members-I Unit-1 Lecture Notes -1. By vamsi r. Pytel A., Kiusalaas J. Mechanics of Materials (2ed., CL, 2011.
• Calculate the number of photons of light with a wavelength of 3000 pm that provide 2 J of energy. Here, 'h' is Planck's constant and 'ν' is the frequency of radiation. Expressing ν in terms of speed of light (c) and wavelength (λ), Subscribe to bartleby learn and ask 30 homework.
• 13. PHYSICS Multiple Choice A 10 kilogram box is moving with a speed of 5 meters per second along a level surface. If the coefficient of kinetic friction between the box and the surface is 0.1 and the coefficient of static friction between the box and the surface is 0.2, which of th

### How many photons in a cm^

Problem #2: If it takes 3.36 x 10-19 J of energy to eject an electron from the surface of a certain metal, calculate the longest possible wavelength, in nanometers, of light that can ionize the metal. Solution: 1) Determine the frequency: E = hν 3.36 x 10-19 J = (6.626 x 10¯ 34 J s) (x) . x = 5.071 x 10 14 s¯ 1. 2) Determine the wavelength: λν = c (x) (5.071 x 10 14 s¯ 1) = 3.00 x 10 8 m/ In 1902, P.Lenard studied how the energy of the emitted photoelectrons varied with the intensity of the light.. He used a carbon arc light, and could increase the intensity a thousand-fold. The ejected electrons hit another metal plate, the collector, which was connected to the cathode by a wire with a sensitive ammeter, to measure the current produced by the illumination The quantity of matter per unit volume, usually specified in kilograms per cubic meter (kg/m3). Sometimes reported in grams per cubic centimeter (gm/cm3). mass density: The threshold energy required by a photon to undergo pair production: 1.02 Me

### Solved: Following up on Exercise 29

When considering a sufficient number of particles or collisions (this is of course the case with a collision rate in the order of 10 34 collisions per second and cubic meter!), the positive values of the scalar product will on average compensate the equally negative scalar products. On statistical average the third term in equation (\ref{term. Septic Tank Size: Detailed Guidance for Septic Tank Capacity vs Usage Computing Septic Tank Capacity Septic system testing, diagnosis, pumping, repair design, defects, alternatives, inspection methods Defects in onsite waste disposal systems, septic tank problems, septic drainfield problems, checklists of system components and things to ask.Septic system maintenance and pumping schedules The mean free path l of photons in homogeneous interstellar dust can be found from Equation (1.4) assuming that the radius of dust grains is 10-7 m. Extinction observations indicate that l ˜ 1 kpc at the position of the Solar System in the Galaxy. What is the number density of dust grains  MCQs - 305HR - Labour Laws Page 1 of 62. MCQs 305 HR - Labour Laws. Few questions are repeated for a reason. Q.1. As per Factories Act Factory means any premises including the precincts thereof where or more workers are working or viewer working on any day of the preceding 12 months, and in any part of which a manufacturing process is being carried on without the aid of power, or is.

### Photon Energies and the Electromagnetic Spectrum Physic

The photons (yellow blobs) carry their energy down through the cell. The photons give up their energy to electrons (green blobs) in the lower, p-type layer. The electrons use this energy to jump across the barrier into the upper, n-type layer and escape out into the circuit Multiply the value by Avogadro's number for the energy of a mole of photons: energy of a mole of photons = (energy of a single photon) x (Avogadro's number) energy of a mole of photons = (3.9756 x 10 -19 J)(6.022 x 10 23 mol -1 ) [hint: multiply the decimal numbers and then subtract the denominator exponent from the numerator exponent to get. number of states per cubic meter per Joule of energy number of states per cubic meter times Joule energy number of states per cubic meter The product of density of states function and Fermi-Dirac function is the hole concentration per unit energy. the electron concentration per unit energy. the electron concentration per unit volume 4. the hole. WORK UNIT NUMBER 7. PERFORMING ORGANIZATION NAME(S) AND ADDRESS(ES) Kilogram per cubic meter (kg m -3) Pound-Force (lbf avoirdupois) 4.448 222 Newton (N) (90 to 250 km), UV photons emitted from a collisional blast wave form a hot -plasma sphere know

Let's see - my MW is ~ .35 x .25 x .5 M, so ~ .044 cubic meters. 30 x 30 x 30 = 27,000, over 600,000 times the volume (OK, that radiated power isn't evenly distributed through that space, but good enough to make the point). Combine those two effects, and it should be obvious your router won't melt a Barbie sized marshmallow given a century to. - cubic meters to cubic feet - gallons to liters - cubic feet to gallons Because the unit of length is the meter, and volume is m · m · m, the unit of volume (V) is m 3. Parts Per Million (ppm) Converter. Collecting Rain. Energy to Heat Water. Iecost Calculation Program Atomic number, abbreviated Z, is the number of protons in an atom's nucleus. For example, the Z's of beryllium, iron, and uranium are 4, 26, and 92, respectively. Z is a property of individual atoms. In contrast, density is a bulk property, and is expressed as mass per unit volume, e.g., grams per cubic centimeter about 1022 atoms in a cubic centimeter of crystal, but there are only about 1010 /cm3 free electrons in silicon -only 1 in one trillion atoms. Carriers Electrons and holes are called carriers -because they can carry current, i.e. when they move around the crystal, a current is produced The number of carriers per volume is called carrie If the original unit is less than the one we want to get, the amount will be divided by $$1000$$ the same number of times as the number of rows that have to be climbed in the table above. If the original unit is larger than the one we want to get, the amount will be multiplied by $$1000$$ the same number of times as the number of rows. 1000 (1 kilometer= 1000 meters) Why do we need at least 70 kVp to make characteristic x-rays? The tungsten atom has a K-shell binding energy of 69.5 keV: this means that we need at least 70 kVp set on the control panel in order to knock this electron from it's orbit and produce a characteristic x-ray

Specific Fuel Oil Consumption Definition Consumption of fuel oil per unit energy at out put shaft is known as Specific fuel oil consumption.Unit of specific fuel oil consumption is Kg/kWh or g/bhph .Or we can define in another way ie, mass of fuel oil consumed per average shaft power developed by the engine at the same tim MCQ on Fluid Mechanics and Hydraulics. 1.The mass per unit volume of a liquid at a standard temperature and pressure is called. Specific weight; Mass density (Ans) Specific gravity; None of these; 2.The weight per unit volume of a liquid at a standard temperature and pressure is called 1/2π√ k 2 /h.g; 1/2π√ h.g/k 2; 60.One cubic metre.   • Well pump replacement near me.
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